- This topic has 7 replies, 2 voices, and was last updated 11 years, 2 months ago by Anonymous.
September 5, 2012 at 5:14 pm #1397Anonymous
I want to model some loops and the n-terminus of a protein.
The n-terminus is 45 residues long and I know the positions of the residues 14-20.
So I have created a homology model of my protein with these residues in correct position and now want to use Rosetta to improve the loops and the n-terminus before and after these 6 residues that I know.
But when I run the simulation, exactly this 6 residues are missing and I can’t explain why. I have now tried many things, especially I tried all posibilities with the loop file but nothing changed. And yes, the residues are really there in the pdb file.
What have I done wrong / how could I solve this problem?
I also have an additional question:
What is the meaning of the third number in the loop file? In the manual I find that it is the “Cut point residue number”. Could someone explain me what is meant by this? I couldn’t find any further information.
Thank you very much for your answers!!!
My input file and my loop file are like this:
-loops:frag_sizes 9 3 1
-loops:frag_files mc4_09 mc4_03 none
LOOP 1 13 13 0 0
LOOP 20 44 0 0 0
LOOP 104 118 0 0 0
LOOP 187 190 0 0 0
LOOP 262 274 0 0 0
September 5, 2012 at 5:27 pm #7752Anonymous
“And yes, the residues are really there in the pdb file. “
Did you check that the occupancy column is nonzero, and that all residues have all four backbone heavy atoms (N, CA, C, O) defined? What happens if you run it through score_jd2 with -out:pdb active (does the result PDB have all the residues or not)? Post the PDB if none of those help fix it and I’ll take a look.
“Cut point residue number”
For KIC-style loop modeling, this is irrelevant and does nothing. For CCD-style, it’s where the loop will break during the pre-re-closure diversification stage. Have you read the papers on how CCD works? (CCD in general, http://www.ncbi.nlm.nih.gov/pubmed/12717019, CCD in Rosetta, http://www.ncbi.nlm.nih.gov/pubmed/17825317)
September 5, 2012 at 5:29 pm #7753Anonymous
Also, I’m not really sure loop modeling does termini – I think quick_ccd will for your perturbation stage, but I know KIC cannot for the refinement.
September 5, 2012 at 5:38 pm #7754Anonymous
I have to check about “What happens if you run it through score_jd2 with -out:pdb active (does the result PDB have all the residues or not)? “
But yes the occupancy column is nonzero and this is what I found in the manual:
“quick_ccd can also remodel termini”
I have uploaded the pdb as a txt file because I saw that pdb files can’t be uploaded. strange?
September 5, 2012 at 5:49 pm #7757Anonymous
Thank you very much! I thought it is 0.00xx so not zero. Apparently I was mistaken.
I’m running now the calculation and will see what happens!
September 5, 2012 at 5:42 pm #7755Anonymous
“I have uploaded the pdb as a txt file because I saw that pdb files can’t be uploaded. strange?”
This is off-the-shelf forum software, it blocks all extensions it doesn’t recognize. Renaming to .txt is correct.
Residues 14-19 have occupancies of zero. Change the 0.00 column (third from the left) to some other value.
September 5, 2012 at 5:44 pm #7756Anonymous
Oh, yeah, there’s a flag for it too: “-ignore_zero_occupancy false” should have the same effect as fixing the input PDB.
September 5, 2012 at 5:53 pm #7758Anonymous
What has happened is that you have triple-digit B-factors in the next column. PDBs are column-indexed, not whitespace-delimited. This means that that absence of a space between columns does not mean that there isn’t a column break. So, for atom #101, the string “0.00146.25” means “occupancy of 0.00, B-factor of 146.25”. Most PDBs have B-factors of two digits or fewer at most positions, so there’s usually an obvious column break there.
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